Zn(s) + H2SO4(aq) 飩? ZnSO4(aq) + H2(g)
Can somebody please help me with this, i'm just confused....What volume of 0.10 mol/dm3 sulphuric acid reacts with 1 g of zinc powder?
Moles Zn = 1 g / 65.38 g/mol=0.015
the ratio between Zn and H2SO4 is 1 : 1
moles H2SO4 needed = 0.015
V = 0.015 mol / 0.10 mol/dm^3 =0.15 L =%26gt; 150 mLWhat volume of 0.10 mol/dm3 sulphuric acid reacts with 1 g of zinc powder?
153 microlitres of H2SO4 will react with 1 gram of Zinc.
Try using the molar equivalancy. Here 1 mole of H2SO4 reacts with 1 mole of Zn. the conc of H2SO4 is given as 0.1 mol/ml so it means 9.807 gm/ml now 65.4 grams of Zinc reacts with 98.07 ( molar weights ) so calculate the amount of H2SO4 that reacts with 1 gram of Zinc noe divide the value that you obtain by the conc of H2SO4 and there you will get the volume.
No comments:
Post a Comment